What are the Odds?
Posted: Tue Nov 07, 2017 3:27 pm
While this article is posted in the "So Craps is New to You and You Don't Have a Clue!" sub-board, the fact is the majority of craps veterans don't have a clear understanding of the odds of the game as well. To that end, I'm going to spend some time here over the next couple of months going through some of the more interesting bets at craps and your chances of winning with them. I won't be adding any skews to the calculations - by that I mean I won't go into things like "if your SRR is 1.728 then the odds of you tossing thirteen tens on any give hand are . . . " We're going to look at the base "random" odds on various bets. It's up to you to determine if you have the skills to beat those odds.
What if I told you I could turn $1 into $27,000 in three rolls of the dice? Would you call "bullshit" on that one? It's not complicated. Toss a $1 chip to the stickman and call "Dollar Midnight (12)." Set the dice and toss a twelve. It pays $30 - $1. Parlay that bet and toss a second twelve. It pays $900. Parlay that bet and toss a third twelve. It pays $27,000. Holy Freshman First Semester at Harvard (tuition only - excluding room and board), Batman. So here's how you arrive at that number. The payoff on the $1 bet on the twelve is $30 to $1. Toss three twelves in a row and parlay the first two bets and it looks like this: 30 X 30 X 30 - 27,000. Now, what are the odds that you'll actually THROW three twelves in a row. Well, there is one twelve out of thirty-six combinations of the dice, making the odds 35 - 1. So we do the math on this one the same way: 35 X 35 X 35 = 42,875. That means you would essentially burn $42,875 trying to win $27,000 one time. It's like going camping and using $15,875 in dollar bills as fire starters.
Have you ever seen a shooter toss three 12's in a row? I've seen it several times. In fact, on one occasion I personally tossed six consecutive 12's on a come-out series where I was betting and setting for the Horn numbers. What are the odds of that? LOL. My calculator wants to go into ERROR mode. It's somewhere around 1 in 1.83 billion, as I recall. How many of those hits did I parlay? Not a one.
For those of us who play craps - it is without a doubt the greatest game in the casino. You can make money faster on a hot table than in any other game in the house. But you can also lose money faster.
Let's talk some more about odds and betting. But first - the dreaded 36 possible combinations of the dice discussion.
Each die has six sides. Each side is numbered with 1 thru 6 pips or spots. Let's say the left die is green and the right die is red - simply so it's easier to track what's happening in this explanation. Now let's get the total number of sides on the dice. Six on each die, so 6 X 6 is 36. That's 36 possible outcomes. They are:
1-1, 1-2, 1-3, 1-4, 1-5, 1-6
2-1, 2-2, 2-3, 2-4, 2-5, 2-6
3-1, 3-2, 3-3, 3-4, 3-5, 3-6
4-1, 4-2, 4-3, 4-4, 4-5, 4-6
5-1, 5-2, 5-3, 5-4, 5-5, 5-6
6-1, 6-2, 6-3, 6-4- 6-5, 6-6
Now, it you look at these combinations you'll notice a couple of things. First off, some numbers can only be rolled one way. These numbers are 1-1, 2-2, 3-3, 4-4, 5-5, and 6-6. The hard four, hard six, hard eight and hard ten are displayed in the hardway box on the layout. Typically the hard four and ten pay 7 - 1 and the hard six and eight pay 9 - 1. Why do they pay different amounts? Because there are two ways each to roll the easy six or eight, knocking off the hard six or eight, but there's only one way each to roll the easy four or ten. Hence the different pay outs. Hardway bets stay up until the number you have wagered is knocked off either by an easy way rolling or by the seven.
The 1-1 and 6-6 are displayed in the prop box area. Variously called aces, post holes, snake eyes, midnight, all the spots we got, high-low, etc., these are one roll bets. Their fate is decided on the next roll of the dice. Hence the higher odds.
Now, the rest of the numbers are "easy way" numbers. That means there are two or more ways to roll that number. The three and eleven are proposition bet numbers. The three can roll 2-1 or 1-2. Some of you are going to be confused by that so think back on that green die - red die I mentioned above. The green die rolls 2 and the red die rolls 1. Then on the next toss the green die rolls 1 and the red die rolls 2. Or just look at that chart above. On the first line you'll see 1-2. on the second line you see 2-1. So there are 2 ways out of 36 possible combinations that add up to three and two ways that add up to eleven. Instead of paying $30 - 1 like the two or twelve craps as mentioned at the top of the page - the three and eleven pay $15 - $1.
Armed with this knowledge you can calculate the probabilities of each number rolling. I'll fill you in with the totals:
The 4 and 10 will roll three ways each
The 5 and 9 will roll four ways each
The 6 and 8 will roll five ways each
The 7 will roll six ways
Now here is where a lot of people go wrong when building betting strategies. They attempt to combine wagers into a single bet, screw up on the odds calculations and cost players a ton of money. Let me explain. We'll take a $10 game and utilize place bets on the six and eight at $12 each. There's a system that's been sold for many years that claims to beat the odds at craps. The strategy recommends Place betting the six and eight only. It claims you have 10 ways to win versus 6 ways to lose, giving you something like a 1.67% positive expectation (10/6). You have 5 ways to win on the six and 5 ways to win on the 8. But the system seller forgets to mention that you have a total of $24 action ($12 each on the six and eight). Result? Every time the seven shows you're going to lose $24. Now let's plug in the numbers:
5 wins at $14 = $70
6 losses at $24 - $144
Net = minus $74
So much for THAT systems.
There are other ways we step out of bounds from time to time when calculating "odds." For example, let's say I wanted to know what the odds were that the four, five or six would roll on the next toss. There are three ways to roll the four, four ways to roll the five, five ways to roll the six. That's twelve of thirty-six combinations, so it looks like the answer should be 3 - 1 against, but the correct answer is 2 - 1 against. That's because three is the sum of all possible outcomes. That includes the possibility that it will happen - or that it won't happen. When we say the odds are 1 in 3 we're also saying that there's two ways of the event not happening versus one way of it happening.
Thoroughly confused? Don't sweat it. Even the old farts hanging around here are struggling with some of this. I'll let you mull that over a bit (and check my math . . . after all, I'm one of the old farts I mentioned) and in my next post I'll talk about things like the odds of a particular number showing on the next roll.
What if I told you I could turn $1 into $27,000 in three rolls of the dice? Would you call "bullshit" on that one? It's not complicated. Toss a $1 chip to the stickman and call "Dollar Midnight (12)." Set the dice and toss a twelve. It pays $30 - $1. Parlay that bet and toss a second twelve. It pays $900. Parlay that bet and toss a third twelve. It pays $27,000. Holy Freshman First Semester at Harvard (tuition only - excluding room and board), Batman. So here's how you arrive at that number. The payoff on the $1 bet on the twelve is $30 to $1. Toss three twelves in a row and parlay the first two bets and it looks like this: 30 X 30 X 30 - 27,000. Now, what are the odds that you'll actually THROW three twelves in a row. Well, there is one twelve out of thirty-six combinations of the dice, making the odds 35 - 1. So we do the math on this one the same way: 35 X 35 X 35 = 42,875. That means you would essentially burn $42,875 trying to win $27,000 one time. It's like going camping and using $15,875 in dollar bills as fire starters.
Have you ever seen a shooter toss three 12's in a row? I've seen it several times. In fact, on one occasion I personally tossed six consecutive 12's on a come-out series where I was betting and setting for the Horn numbers. What are the odds of that? LOL. My calculator wants to go into ERROR mode. It's somewhere around 1 in 1.83 billion, as I recall. How many of those hits did I parlay? Not a one.
For those of us who play craps - it is without a doubt the greatest game in the casino. You can make money faster on a hot table than in any other game in the house. But you can also lose money faster.
Let's talk some more about odds and betting. But first - the dreaded 36 possible combinations of the dice discussion.
Each die has six sides. Each side is numbered with 1 thru 6 pips or spots. Let's say the left die is green and the right die is red - simply so it's easier to track what's happening in this explanation. Now let's get the total number of sides on the dice. Six on each die, so 6 X 6 is 36. That's 36 possible outcomes. They are:
1-1, 1-2, 1-3, 1-4, 1-5, 1-6
2-1, 2-2, 2-3, 2-4, 2-5, 2-6
3-1, 3-2, 3-3, 3-4, 3-5, 3-6
4-1, 4-2, 4-3, 4-4, 4-5, 4-6
5-1, 5-2, 5-3, 5-4, 5-5, 5-6
6-1, 6-2, 6-3, 6-4- 6-5, 6-6
Now, it you look at these combinations you'll notice a couple of things. First off, some numbers can only be rolled one way. These numbers are 1-1, 2-2, 3-3, 4-4, 5-5, and 6-6. The hard four, hard six, hard eight and hard ten are displayed in the hardway box on the layout. Typically the hard four and ten pay 7 - 1 and the hard six and eight pay 9 - 1. Why do they pay different amounts? Because there are two ways each to roll the easy six or eight, knocking off the hard six or eight, but there's only one way each to roll the easy four or ten. Hence the different pay outs. Hardway bets stay up until the number you have wagered is knocked off either by an easy way rolling or by the seven.
The 1-1 and 6-6 are displayed in the prop box area. Variously called aces, post holes, snake eyes, midnight, all the spots we got, high-low, etc., these are one roll bets. Their fate is decided on the next roll of the dice. Hence the higher odds.
Now, the rest of the numbers are "easy way" numbers. That means there are two or more ways to roll that number. The three and eleven are proposition bet numbers. The three can roll 2-1 or 1-2. Some of you are going to be confused by that so think back on that green die - red die I mentioned above. The green die rolls 2 and the red die rolls 1. Then on the next toss the green die rolls 1 and the red die rolls 2. Or just look at that chart above. On the first line you'll see 1-2. on the second line you see 2-1. So there are 2 ways out of 36 possible combinations that add up to three and two ways that add up to eleven. Instead of paying $30 - 1 like the two or twelve craps as mentioned at the top of the page - the three and eleven pay $15 - $1.
Armed with this knowledge you can calculate the probabilities of each number rolling. I'll fill you in with the totals:
The 4 and 10 will roll three ways each
The 5 and 9 will roll four ways each
The 6 and 8 will roll five ways each
The 7 will roll six ways
Now here is where a lot of people go wrong when building betting strategies. They attempt to combine wagers into a single bet, screw up on the odds calculations and cost players a ton of money. Let me explain. We'll take a $10 game and utilize place bets on the six and eight at $12 each. There's a system that's been sold for many years that claims to beat the odds at craps. The strategy recommends Place betting the six and eight only. It claims you have 10 ways to win versus 6 ways to lose, giving you something like a 1.67% positive expectation (10/6). You have 5 ways to win on the six and 5 ways to win on the 8. But the system seller forgets to mention that you have a total of $24 action ($12 each on the six and eight). Result? Every time the seven shows you're going to lose $24. Now let's plug in the numbers:
5 wins at $14 = $70
6 losses at $24 - $144
Net = minus $74
So much for THAT systems.
There are other ways we step out of bounds from time to time when calculating "odds." For example, let's say I wanted to know what the odds were that the four, five or six would roll on the next toss. There are three ways to roll the four, four ways to roll the five, five ways to roll the six. That's twelve of thirty-six combinations, so it looks like the answer should be 3 - 1 against, but the correct answer is 2 - 1 against. That's because three is the sum of all possible outcomes. That includes the possibility that it will happen - or that it won't happen. When we say the odds are 1 in 3 we're also saying that there's two ways of the event not happening versus one way of it happening.
Thoroughly confused? Don't sweat it. Even the old farts hanging around here are struggling with some of this. I'll let you mull that over a bit (and check my math . . . after all, I'm one of the old farts I mentioned) and in my next post I'll talk about things like the odds of a particular number showing on the next roll.